NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.3

1. Find

(a) 35 – (20)

Ans: 35 – (20) = 15

(b) 72 – (90)

Ans: 72 – (90)

= 72 + (additive inverse of 90)

= 72 + (–90)

= – 18

Ans: (–15) – (–18)

= (–15) + (additive inverse of – 18)

= (–15) + (18)

= 3

(d) (–20) – (13)

Ans: (–20) – (13)

= (–20) + (additive inverse of 13)

= (–20) + (–13)

= –33

(e) 23 – (– 12)

Ans: 23 – (–12)

= 23 – (additive inverse of –12)

= 23 + (12)

= 35

(f) (–32) – (– 40)

Ans: (–32) – (– 40)

= (–32) – (additive inverse of –40)

= (–32) + (40)

= 8

2. Fill in the blanks with >, < or = sign.

(a) (– 3) + (– 6) ______ (– 3) – (– 6)

Ans: (– 3) + (– 6) ______ (– 3) – (– 6)

–9 ______ (– 3) + (6)

–9 < 3

(b) (– 21) – (– 10) _____ (– 31) + (– 11)

Ans: (– 21) – (– 10) _____ (– 31) + (– 11)

(– 21) + 10 _____ (– 31) + (– 11)

–11 > –42

Ans: 45 – (– 11) ______ 57 + (– 4)

45 + 11 ______ 53

56 > 53

(d) (– 25) – (– 42) _____ (– 42) – (– 25)

Ans: (– 25) – (– 42) _____ (– 42) – (– 25)

(– 25) + 42 _____ (– 42) + 25

17 > –17

3. Fill in the blanks.

(a) (– 8) + _____ = 0

Ans: (– 8) + 8 = 0

(b) 13 + _____ = 0

Ans: 13 + (–13) = 0

Ans: 12 + (– 12) = 0

(d) (– 4) + ____ = – 12

Ans: (– 4) + (–8) = – 12

(e) ____ – 15 = – 10

Ans: 5 – 15 = – 10

4. Find

(a) (– 7) – 8 – (– 25)

Ans: (– 7) – 8 – (– 25)

= (– 7) + (–8) + (25)

= (– 15) + (25)

= 10

(b) (– 13) + 32 – 8 – 1

Ans: (– 13) + 32 – 8 – 1

= (– 13) + 32 + (– 8) + (– 1)

= 32 + (– 13) + (– 8) + (– 1)

= 32 + (– 13) + (– 9)

= 32 + (– 22)

= 10

Ans: (–7) + (–8) + (–90)

= (–7) + (–8) + (–90)

= (–15) + (–90)

= (–105)

(d) 50 – (–40) – (–2)

Ans: 50 – (–40) – (–2)

= 50 +40 + 2

= 92

Click Here to Watch Video Solution of Exercise 6.3

Exercise 6.1

Exercise 6.2

NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.3